Answer: Our required probability is 39.69%.
Explanation:
Since we have given that
Probability of a bowler getting a strike during a particular frame = 63%
Number of frames are performed = 2
We need to find the probability that the bowler would be most likely to get a strike in each of the two frames.
So, it becomes,
![(63)/(100)* (63)/(100)=(0.63)^2\\\\=0.3969\\\\=39.69\%](https://img.qammunity.org/2020/formulas/mathematics/high-school/8i3wn03jdugj36idzjp753imzz65bxuf4s.png)
Hence, Our required probability is 39.69%.