Question

Instructions Write a value-returning function, isVowel, that returns the value true if a given character is a vowel and otherwise returns false. For the input E, your output should look like the following: E is a vowel: 1 When printing the value of a bool, true will be displayed as 1 and false will be displayed as 0.

Answer 1

This function returns a Boolean value in the form of Boolean variable which shows whether the parameter is a vowel or not.

return result;

The c++ program for the above is given which shows the output in the given format.

#include <stdio.h>

#include <iostream>

using namespace std;

bool isVowel(char c);

bool isVowel(char c)

c == 'i'

int main() {

char data;

cout<<"This program will check if the entered character is a vowel."<<endl;

cout<<"Enter any alphabet"<<endl;

cin>>data;

cout<<endl<<data <<" is a vowel: "<<isVowel(data)<<endl;

return 0;

}

OUTPUT

This program will check if the entered character is a vowel.

Enter any alphabet

o

o is a vowel: 1

Step-by-step explanation:

The function which accepts an alphabet and returns a value is shown below.

bool isVowel(char c)

The function isVowel() accepts an alphabet which is stored in a character variable and returns a Boolean value.

bool isVowel(char c)

This function declares a Boolean variable, result, and initializes it to false.

bool result=false;

The parameter is matched will all the vowels in both lower case and upper case. If the character matches, i.e., if it is a vowel, the Boolean variable is initialized to true. If the alphabet does not matches, there is no change in the value of Boolean variable result, i.e., result holds the value false.

if(c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u' || c == 'A' || c =='E' || c =='I' || c =='O' || c =='U')

result = true;