231k views
1 vote
A 15. μF capacitor is connected to a 50. V battery and becomes fully charged. The battery is removed and a slab of dielectric that completely fills the space between the plates is inserted. If the dielectric has a dielectric constant of 5.0, what is the voltage across the capacitor's plates after the slab is inserted?

User XMozart
by
5.1k points

1 Answer

2 votes

Answer:

voltage across the capacitor's is 75 μF

Step-by-step explanation:

given data

capacitor = 15 μF

voltage = 50V

dielectric constant k = 5

to find out

voltage across the capacitor's

solution

we will find here voltage across the capacitor's by this formula

voltage across the capacitor's = k
C_(o)

here k is 5 and
C_(o) = 15

put these value we get

voltage across the capacitor's = k
C_(o)

voltage across the capacitor's = 5 ( 15 ) = 75 μF

so voltage across the capacitor's is 75 μF

User Mark Irvin
by
5.0k points