Question

If the specific heat capacity of water is 4.18 J/g·oC , how much of heat energy is needed to raise the temperature of 10.00 g of liquid water from 14.1 oC to 16.2 oC?

Answer 1

Step-by-step explanation:

As it is known that relation between specific heat and heat energy is as follows.

Q =
`mC \Delta T`

where, Q = heat energy

m = mass

C = specific heat capacity = 4.18
`J/g ^(o)C`

`\Delta T` = change in temperature

Therefore, putting the given values into the above formula as follows.

Q =
`mC \Delta T`

=
`10 g * 4.18 J/g ^(o)C * (16.2 - 14.1)^(o)C`

= 87.78 J

Thus, we can conclude that the heat energy needed to raise the temperature of 10.00 g of liquid water from
`14.1^(o)C` to
`16.2^(o)C` is 87.78 J.