Answer : The equilibrium constant
for the reaction is, 0.869
Explanation :
First we have to calculate the concentration of
.


The balanced equilibrium reaction is,

Initial conc. C 0
At eqm. conc.

As we are given,
The percent of dissociation =
= 37 % = 0.37
Now we have to calculate the equilibrium constant for the reaction.
The expression of equilibrium constant for the reaction will be :
![K_c=([NO_2]^2)/([N_2O_4])](https://img.qammunity.org/2020/formulas/physics/college/qjqdoekzbudhpleet02icllsrildnndyp1.png)

Now put all the values in this expression, we get :


Therefore, the equilibrium constant
for the reaction is, 0.869