Question

If you can solve it.Thanks in advance

Answer 1

`f(g(x))=(1)/((x^(2)+1)^(2)) +\sqrt[3]{x^(2)+1}`

Explanation:

we have

`f(x)=x^(2) +\frac{1}{\sqrt[3]{x}}`

`g(x)=(1)/(x^(2)+1)`

we know that

In the function

`f(g(x))`

The variable of the function f is now the function g(x)

substitute

`f(g(x))=((1)/(x^(2)+1))^(2) +\frac{1}{\sqrt[3]{((1)/(x^(2)+1))}}`

`f(g(x))=(1)/((x^(2)+1)^(2)) +\sqrt[3]{x^(2)+1}`