Question

"The combustion of ethylene proceeds by the reaction C2H4(g) + 3O2(g) → 2CO2(g) + 2H2O(g) When the rate of disappearance of O2 is 0.23 M s-1, the rate of disappearance of C2H4 is ________ M s-1."

Answer 1

The rate of disappearance of C2H4 is 0.077 M s-1.

Step-by-step explanation:

The rate of disappearance of C2H4 can be determined by comparing the coefficients of C2H4 and O2 in the balanced equation:

C2H4(g) + 3O2(g) → 2CO2(g) + 2H2O(g)

Since the coefficient of O2 is 3 and the rate of disappearance of O2 is 0.23 M s-1, the rate of disappearance of C2H4 is 0.23/3 = 0.077 M s-1. Therefore, the rate of disappearance of C2H4 is 0.077 M s-1.

Answer 2

The rate of disappearance of
`C_2H_4` is 0.0766 M/s.

Step-by-step explanation:

`C_2H_4(g)+3O_2(g)\rightarrow 2CO_2(g)+2H_2O(g)`

Rate of the reaction = R

`R=-(1)/(1)(d[C_2H_4])/(dt)=-(1)/(3)(d[O_2])/(dt)`

[te]R=\frac{1}{2}\frac{d[CO_2]}{dt}=\frac{1}{2}\frac{d[H_2O]}{dt}[/tex]

Rate of disappearance of
`O_2` =0.23 M/s

Rate of disappearance of
`O_2=3* R`

`0.23 M/s=3* R`

R =0.07666 M/s

Rate of disappearance of
`C_2H_4=1* R`

`(d[C_2H_4])/(dt)=1* 0.23 m/s=0.0766 M/s`

The rate of disappearance of
`C_2H_4` is 0.0766 M/s.