A charged particle (q = -8.0 mC), which moves in a region where the only force acting on the particle is an electric force, is released from rest at point A. At point B the kinetic energy of the particle

asked Oct 27, 2020 33.3k views

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2 votes

Answer:600 V

Step-by-step explanation:

Given

Q=-8 mC

W=4.8 J

And we know

W=QV

V_b-V_a=V_(ba)

$4.8=\left ( 8* 10^(-3) \right )V_(ba)$

V_(ba)=0.6* 10^(-3)

V_(ba)=600 V

Ramesh S answered Oct 31, 2020

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