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A series of chemicals were added to some AgNO3(aq). NaCl(aq) was added first to the silver nitrate solution to produce a precipitate. NH3(aq) was then added to produce a clear solution. HNO3(aq) was added last to result in a precipitate. Write a balanced net ionic equation for each of the three steps.

User Sophonias
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Answer:

First, precipitate of AgCl is formed. Second, a soluble complex of silver and ammonia is formed. Third, AgCl is reproduced due to disappearance of ammonia complex in presence of
HNO_(3).

Step-by-step explanation:

In presence of NaCl,
AgNO_(3) forms an insoluble precipitate of AgCl.

Reaction:
Ag^(+)(aq.)+Cl^(-)(aq.)\rightarrow AgCl(s)

In presence of
NH_(3), AgCl gets dissolved into solution due to formation of soluble
[Ag(NH_(3))_(2)]^(+) complex.

Reaction:
AgCl(s)+2NH_(3)(aq.)\rightarrow [Ag(NH_(3))_(2)]^(+)(aq.)+ Cl^(-)(aq.)

In presence of
HNO_(3),
[Ag(NH_(3))_(2)]^(+) complex gets destroyed and free
Cl^(-) again reacts with free
Ag^(+) to produce insoluble AgCl

Reaction:
[Ag(NH_(3))_(2)]^(+)(aq.)+2H^(+)(aq.)+Cl^(-)(aq.)\rightarrow AgCl(s)+2NH_(4)^(+)(aq.)

User DMarczak
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