Write an equation in slope-intercept form of the line containing the points (3, -1) and (6, 7).

Question

asked Jun 3, 2020 49.5k views

1 Answer

Joseadrian · Answer 1 · 2020-06-08T13:53:38+0000

Answer:

y= 8/3 x - 9

Explanation:

The equation of any given line is y=mx+b

where m is the slope and b the intercept point with y=axis.

First lest obtain the slope by using slope's equations

m=(y_(2)-y_(1))/(x_(2)-x_(1))

Where (x2,y2)= (6,7) and (x1,y1)= (3,-1)

$m=\frac{7-(-1){6-3}$

Thus we have that our slope is 8/3

Now lets found our intercept point with 'y' axis.

We can use the first point (3,-1)

-1= 8/3 * 3 + b

b=-9

The equation is: y= 8/3 x - 9