Question

A 58 kg skier starts at rest from a 24.0 m high hill. They travel to the bottom and then up a second hill to a height of 19.0 m. How much kinetic energy do they have at the top of the second hill?

Answer 1

10.791 kJ

Step-by-step explanation:

Given that,

Mass of the skier, m = 58 kg

Initial position, h₁ = 24 m

Final position, h₂ = 19 m

We need to find the kinetic energy do they have at the top of the second hill.

Using the conservation of energy for both positions.

`v_1=√(2gh_1) \\\\=√(2* 9.8* 24) \\\\=21.68\ m/s`

And

`v_2=√(2gh_2) \\\\=√(2* 9.8* 19) \\\\=19.29\ m/s`

Kinetic energy :

`K=(1)/(2)mv_2^2\\\\K=(1)/(2)* 58* 19.29^2\\\\=10791.01 J\\\\=10.791\ kJ`

So, the kinetic energy they have at the top of the second hill is 10.791 kJ.