Question

In the future, astronomers discover a solid moon around a planet orbiting one of the nearest stars. This moon has a diameter of 1948 km and a mass of 1.6 × 1022 kg. What is its density?

Answer 1

The density is 4134.37 kg/m³.

Step-by-step explanation:

Given that,

Diameter = 1948 km

Mass
`m=1.6*10^(22)\ kg`

We need to calculate the volume of moon

`V= (4)/(3)\pi* r^3`

`V=(4)/(3)*\pi*(974*10^(3))^3`

`V=3.870*10^(18)\ m^3`

We need to calculate the density

`\rho=(m)/(V)`

Where, m = mass

V = volume

Put the value into the formula

`\rho=(1.6*10^(22))/(3.870*10^(18))`

`\rho=4134.37\ kg/m^3`

Hence, The density is 4134.37 kg/m³.