Question

Write the molecular, ionic, and net ionic equations for the reaction of a: hcl with koh, b: hcho2 with lioh and c: n2h4 with hcl. Include states in your answer.

Answer 1

Here's what I get.

Step-by-step explanation:

a. HCl + KOH

`\rm Molecular: KOH(aq)+ HCl(aq) \longrightarrow \, KCl(aq) + H_(2)O(l)\\\rm Ionic: K^(+)(aq) + OH^(-)(aq)+ H^(+)(aq) + Cl^(-)(aq) \longrightarrow \, K^(+)(aq)+ Cl^(-)(aq) + H_(2)O(l)\\\rm Net ionic: OH^(-)(aq)+ H^(+)(aq) \longrightarrow \, H_(2)O(l)\\`

b. HCHO₂ + LiOH

Only the first H in HCHO₂ is acidic

`\rm Molecular: HCHO_(2)(aq)+ LiOH(aq) \longrightarrow \, LiCHO_(2)(aq) + H_(2)O(l)\\\rm Ionic: HCHO_(2)(aq) + Li^(+)(aq) + OH^(-)(aq) \longrightarrow \, Li^(+)(aq)+ CHO_(2)^(-)(aq) + H_(2)O(l)\\\rm Net ionic: HCHO_(2)(aq) + OH^(-)(aq) \longrightarrow \, CHO_(2)^(-)(aq) + H_(2)O(l)\\`

c. N₂H₄ + HCl

Both N atoms in N₂H₄ are basic, so the compound reacts with 2 mol of HCl.

`\rm Molecular: N_(2)H_(4)(aq)+ 2HCl(aq) \longrightarrow \, N_(2)H_(6)Cl_(2)(aq) \\\rm Ionic: \qquad N_(2)H_(4) (aq) + 2H^(+)(aq) + 2Cl^(-)(aq) \longrightarrow \, N_(2)H_(6)^(+)(aq) + 2Cl^(-)(aq)\\\rm Net ionic: \ N_(2)H_(4) (aq) + 2H^(+)(aq) \longrightarrow \, N_(2)H_(6)^(+)(aq)\\`