Answer:
- sqrt (3) - i
Explanation:
z = 2(cos7π/6 +isin7π/6)
cos7π/6 = cos(π/6+π) = - cos(π/6) = - √3 /2
sin7π/6 = sin(π/6+π) = - sin(π/6) = - 1 /2
so : z = 2( - √3 /2+i(- 1 /2))
z= - √3 - i .....(standard form)
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