Answer:
First option: 5 to the power of one sixth (
)
Explanation:
It is important to remember the following:
![\sqrt[n]{\sqrt[m]{a} }=\sqrt[nm]{a}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ulewpzeovf3s4mtdai17rvcrvg82cp7kmi.png)
![\sqrt[n]{a}=a^{(1)/(n)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/tdy3uzp5yflew0pdyw8u3hgbv8hn209c5u.png)
In this case, given:
![\sqrt[2]{\sqrt[3]{5} }](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nay4j1te5amliilebqtpwxjwlb0q4pbulq.png)
You can identify that:
and

Therefore, knowing this, you can conclude that:
![=\sqrt[2*3]{5}=\sqrt[6]{5}=5^{(1)/(6)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vio37no1g7zpomzb095yyvnqzhjvne744y.png)
You can observe that this answer matches with the second option.