Answer:
32.793
Explanation:
Given that your marketing colleague used a known population mean and standard deviation to compute the standard error as 56.8 for samples of a particular size
You don't know the particular sample size but your colleague told you that the sample size is greater than 60.
When n becomes 3n, we get Std error would become instead of
![(std dev)/(√(n) )](https://img.qammunity.org/2020/formulas/mathematics/college/6irgrpeo8lnjda7n0anam3petlsfa7kymn.png)
to
![(std dev)/(√(3n) )](https://img.qammunity.org/2020/formulas/mathematics/college/6ohqwle4sse0pnzsygz5u57r87rgezyjtq.png)
Thus we get standard error for new sample size = old se/sqrt 3
=
![(56.8)/(√(3) ) \\=32.793](https://img.qammunity.org/2020/formulas/mathematics/college/lgwldqvlpurj12y7ipimzbbpskkgfcm8lz.png)