Question

Give the coordination number for each metal ion in the following compounds:

(a) [Co(CO3)3]3− (note that CO32− is bidentate in this complex)(b) [Cu(NH3)4]2+
(c) [Co(NH3)4Br2]2(SO4)3
(d) [Pt(NH3)4][PtCl4]
(e) [Cr(en)3](NO3)3
(f) [Pd(NH3)2Br2] (square planar)
(g) K3[Cu(Cl)5]
(h) [Zn(NH3)2Cl2]

Answer 1

The coordination numbers for each metal ion are: (a) 6, (b) 4, (c) 6, (d) 4, (e) 6, (f) 4, (g) 5, (h) 4.

Step-by-step explanation:

The coordination number refers to the number of ligands that are bonded to the central metal ion in a coordination compound. Here are the coordination numbers for each metal ion:

(a) [Co(CO3)3]³⁻: The coordination number is 6 because each carbonate ion (CO3²⁻) is bidentate, meaning it forms two bonds with the cobalt ion.

(b) [Cu(NH3)4]²⁺: The coordination number is 4 because there are four ammonia (NH3) ligands bonded to the copper ion.

(c) [Co(NH3)4Br2]²(SO4)3: The coordination number is 6 because there are four ammonia (NH3) and two bromide (Br⁻) ligands bonded to the cobalt ion.

(d) [Pt(NH3)4][PtCl4]: The coordination number is 4 for both platinum ions because there are four ammonia (NH3) ligands bonded to each platinum ion.

(e) [Cr(en)3](NO3)3: The coordination number is 6 because there are three ethylenediamine (en) ligands bonded to the chromium ion.

(f) [Pd(NH3)2Br2]: The coordination number is 4 because there are two ammonia (NH3) and two bromide (Br⁻) ligands bonded to the palladium ion in a square planar arrangement.

(g) K3[Cu(Cl)5]: The coordination number is 5 because there are five chloride (Cl⁻) ligands bonded to the copper ion.

(h) [Zn(NH3)2Cl2]: The coordination number is 4 because there are two ammonia (NH3) and two chloride (Cl⁻) ligands bonded to the zinc ion.