Answer:
Option C.
Explanation:
We can solve this question by plugging in the values of x and y in the given equations of the options.
A). y =
![(5)/(4)x](https://img.qammunity.org/2020/formulas/mathematics/high-school/p0h04pax3b73yaaeoxhjoswufl2w0gpvrx.png)
Now we plug in the value of x = 100 and y = 135
135 =
![(5)/(4)* 100](https://img.qammunity.org/2020/formulas/mathematics/high-school/ubczhjt3mogai8i40oxppjrzahcjy1kojg.png)
135 = 125
Which is not possible so this equation is not the answer.
B). y =
![(4)/(5)x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/o1oq1qf9kq3m2jwo8a9updcu49btbahkgs.png)
We plug in the value of x = 100 and y = 135
135 =
![(4)/(5)* 100](https://img.qammunity.org/2020/formulas/mathematics/high-school/k1tldcoihdcx6suf0wwb46i9tvy1gml7cv.png)
135 = 80
Again not possible. So this equation is not the required answer.
C). y =
![(5)/(4)x+10](https://img.qammunity.org/2020/formulas/mathematics/high-school/1zmzsl8emv8c52vp5ubj5dyxpbxjojeijb.png)
For x = 100 and y = 135
135 =
![(5)/(4)* 100+10](https://img.qammunity.org/2020/formulas/mathematics/high-school/7d08h2owycw86bi53gkr0om47b9lvujk04.png)
135 = 125 + 10
135 = 135
For x = 200 and y = 260
260 =
![(5)/(4)* 200+10](https://img.qammunity.org/2020/formulas/mathematics/high-school/etstni94dlt8ykteoni1a391pllh648472.png)
260 = 250 + 10
260 = 260
Therefore, the given table satisfies this equation for all values of x and y given in the table.
Option C. is the answer.
D). y =
![(4)/(5)x+55](https://img.qammunity.org/2020/formulas/mathematics/high-school/pc17rtsl6h03d72jjumyvfqiqhdsom6ptc.png)
For x = 100 and y = 135
135 =
![(4)/(5)* 100+55](https://img.qammunity.org/2020/formulas/mathematics/high-school/pbyjn0vt5ytzq6651coa315l3yo8lvol1a.png)
135 = 80 + 55
135 = 135
Now for x = 200 and y = 260
260 =
![(4)/(5)* 200+55](https://img.qammunity.org/2020/formulas/mathematics/high-school/y2hd0f51f9mc7y8vy3mj142dcrcrwymet3.png)
260 = 160 + 55
260 = 215
Which is not possible therefore option D is not the answer.