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(Sec A+tan A) (1- Sin A)

Answer for 11,12

(Sec A+tan A) (1- Sin A) Answer for 11,12-example-1
User Sponge Bob
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2 Answers

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Answer:

11. d. cos A.

12. d. tan^2 A.

Explanation:

11.

(sec A + tan A)(1 - sinA)

= sec A - sec A sin A + tan A - sin A tan A

Convert to sine's and cosine's using sec A = 1/ cos A and tan A = sin A / cos A:

= 1/cos A - sin A / cos A + sin A / cos A - sin^2 A / cos A

= 1 /cos A - sin^2 A / cos A

= (1 - sin^2 A) / cos A Using 1 - sin^ A = cos^2 A:

= cos^2 A / cos A

= cos A.

12.

Now sec^2 A = 1 + tan^2 A and cosec^2 A = 1 + cot^2 A so

(1 + tan^2 A) / (1 + cot^2 A)

= sec^2 A / cosec^2 A

= 1 / cos^2 A / 1 / sin^2 A

= sin^2 A / cos^2 A

= tan^2 A.

User Eskimo
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Explanation:

here is the answer for your question

(Sec A+tan A) (1- Sin A) Answer for 11,12-example-1
(Sec A+tan A) (1- Sin A) Answer for 11,12-example-2
User Lupatus
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