Question

(3x-4)+(x-2)=62 (Geometry)

Answer 1

`x=\Large\boxed{17}`

`AC=\Large\boxed{47}`

Explanation:

Given information

`AC+CB=AB`

`AC=3x-4`

`CB=x-2`

Requirement of the question

`\text{--Determine the value of x}`

`\text{--Determine the value of AC}`

Given equation

`(3x-4)+(x-2)=62`

Combine like terms

`3x-4+x-2=62`

`3x+x-4-2=62`

`4x-6=62`

Add 6 on both sides

`4x-6+6=62+6`

`4x=68`

Divide 4 on both sides

`4x/4=68/4`

`x=\Large\boxed{17}`

Substitute the value into the expression for AC

`AC=3(17)-4`

`AC=51-4`

`AC=\Large\boxed{47}`

Hope this helps!! :)

Please let me know if you have any questions