Question

PQR with P(3, 6), 2-6, 6), R(0, 9); (x, y) = (x-3, y + 7)

оа
Ob
P'(0, 13), O'(-9, 13), R'(-3, 16)
P'(10,3), Q'(1,3), R' (7, 6)
P'(3, 7), e'(-6, 7), R' (0,7)
P'(-3, 13), e' (3, 13), R'(-3, 16)

Answer 1

We have the answer as:

P'(0, 13), O'(-9, 13), R'(-3, 16)

Explanation:

Here, we want to find the coordinates of the image after applying the transformation rule to the pre-image

what the transformation rule is saying is that we subtract 3 from the x-coordinate and add 7 to the y-coordinate

mathematically, we have these as follows;

P’ = (3-3, 6 + 7) = (0,13)

Q’ = (-6-3, 6 + 7) = (-9,13)

R’ ( 0-3, 9 + 7) = (-3, 16)