Question

What is the molality of a solution if 100.0 g of glucose (C&Hi20e) were dissolved into 750. mL of water?

Answer 1

Answer: The molality of solution is 0.740 m.

Step-by-step explanation:

To calculate the mass of solvent (water), we use the equation:

`Density=(Mass)/(Volume)`

Volume of water = 750 mL

Density of water = 1 g/mL

Putting values in above equation, we get:

`1g/mL=\frac{\text{Mass of water}}{750mL}\\\\\text{Mass of water}=750g`

To calculate the molality of solution, we use the equation:

`Molarity=\frac{m_(solute)* 1000}{M_(solute)* W_(solvent)\text{ in grams}}`

Where,

`m_(solute)` = Given mass of solute
`(C_6H_(12)O_6)` = 100.0 g

`M_(solute)` = Molar mass of solute
`(C_6H_(12)O_6)` = 180 g/mol

`W_(solvent)` = Mass of solvent (water) = 750 g

Putting values in above equation, we get:

`\text{Molality of }C_6H_(12)O_6=(100* 1000)/(180* 750)\\\\\text{Molality of }C_6H_(12)O_6=0.740m`

Hence, the molality of solution is 0.740 m.