Question

The pKa of an acid whose Ka = 10–11 is

1011

11

–11

3

–3

Answer 1

Answer: Option (b) is the correct answer.

Step-by-step explanation:

Relation between
`K_(a)` and
`pK_(a)` is as follows.

`pK_(a) = -log K_(a)`

where,
`K_(a)` is the acid dissociation constant.

As value of
`K_(a)` is given as
`10^(-11)`. Therefore, calculating teh value of
`pK_(a)` as follows.

`pK_(a) = -log K_(a)`

= -log (
`10^(-11)`)

= - (-11 × log (10))

= 11

Thus, we can conclude that the
`pK_(a)` of an acid whose
`K_(a) = 10^(-11)` is 11.