Question

A 15.0 g metal sample at 25.0 °c has 250 J of heat added to it. The specific heat of the metal is 0.128 J/g.°c. What is the final temperature?

Answer 1

Answer: The final temperature is
`155.2^oC`

Step-by-step explanation:

To calculate the final temperature, we use the equation:

`Q=mc\Delta T`

where,

Q = heat absorbed = 250 J

m = Mass of the substance = 15 g

c = specific heat capacity of water = 0.128 J/g.°C

`\Delta T` = change in temperature =
`T_2-T_1=(T_2-25^oC)`

Putting values in above equation, we get:

`250J=15g* 0.128J/g.^oC* (T_2-25)\\\\T_2=155.2^oC`

Hence, the final temperature is
`155.2^oC`