Question

When 1500. J of heat is added to 250. g of a metal, its temperature is raised by 25 oc. What is the specific heat capacity of the metal and what is the metal?

Answer 1

Answer: The specific heat capacity of the metal is
`0.24J/g.^oC`

Step-by-step explanation:

To calculate the specific heat of metal, we use the equation:

`Q=mc\Delta T`

where,

Q = heat absorbed = 1500 J

m = Mass of the substance = 250 g

c = specific heat capacity of water = ? J/g.°C

`\Delta T` = change in temperature =
`25^oC`

Putting values in above equation, we get:

`1500J=250g* c* 25^oC\\\\c=0.24J/g.^oC`

Hence, the specific heat capacity of the metal is
`0.24J/g.^oC`