Question

At a certain temperature, the solubility of zinc(I) chromate is (7.0x10^-5) M. What is the Ksp?

Answer 1

Ksp = 4.9 E-9

Step-by-step explanation:

• S = 7.0 E-5 M

• ZrCrO4 ↔ Zr²+ + CrO4²-

solubility: S S S

⇒ Ksp = [ Zr²+ ] * [ CrO4²- ]

⇒ Ksp = S * S = S²

⇒ Ksp = ( 7.0E-5)²

⇒ Ksp = 4.9E-9