Answer:
1/(x^(17/12)y^(5/3))
Explanation:
We assume you want to simplify the expression. The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
(a^b)^c = a^(bc)
1/a^b = a^-b
Using these "all at once", we can add up the exponents of each of the variables:
x^(-2/3 -2·0 -(1/2)(3/2))·y^(-2/3-(1/2)·2) = x^(-2/3-3/4)y^(-2/3-1)
= x^(-17/12)y^(-5/3)
=
![\frac{1}{x^{(17)/(12)}y^{(5)/(3)}}](https://img.qammunity.org/2020/formulas/mathematics/high-school/5b3t246tuk2ktvlej7z1d5q145btc14awi.png)