Question

How many mL. of 0.200 M Pb(NOs)2 solution are needed to obtain 0.875 grams of Pb(NO:)2?

Answer 1

Vsln=13.2mL

Step-by-step explanation:

MwPb(NO3)2=331.2g/mol

⇒ Vsln = (1L Pb(NO3)2/0.200molPb(NO3)2) * (molPb(NO3)2/331.2gPb(NO3)2) * 0.875gPb(NO3)2

⇒ Vsln = 0.0132L (13.2mL)