Question

What is the equation in point-slope form of the line passing through (0, 5) and (−2, 11)? (1 point)

Answer 1

`\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{11}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{11-5}{-2-0}\implies \cfrac{6}{-2}\implies -3 \\\\\\ \begin{array} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-5=-3(x-0) \\\\\\ y-5=-3x\implies y=-3x+5`