Question

By titration, it is found that 95.5 mL95.5 mL of 0.188 M NaOH(aq)0.188 M NaOH(aq) is needed to neutralize 25.0 mL of HCl(aq).HCl(aq). Calculate the concentration of the HClHCl solution.

Answer 1

Answer: The concentration of HCl comes out to be 0.718 M.

Step-by-step explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

`n_1M_1V_1=n_2M_2V_2`

where,

`n_1,M_1\text{ and }V_1` are the n-factor, molarity and volume of acid which is HCl

`n_2,M_2\text{ and }V_2` are the n-factor, molarity and volume of base which is NaOH.

We are given:

`n_1=1\\M_1=?M\\V_1=25.0mL\\n_2=1\\M_2=0.188M\\V_2=95.5mL`

Putting values in above equation, we get:

`1* M_1* 25=1* 0.188* 95.5\\\\M_1=0.718M`

Hence, the concentration of HCl comes out to be 0.718 M.