232k views
2 votes
Find the 100th term of the arithmetic sequence with first term 4 and eighth term 32.

1 Answer

5 votes

Answer:400

Explanation:

Given

First term a=4

and 4th term is 32

i.e.


a_8=32

let d be the common difference

a+7d=32

a=4

therefore

7d=32-4=28

d=4

Therefore 100 th term is


a_(100)=a+99d=4+99\cdot 4=400

User Youssri Abo Elseod
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories