Question

What is the value of p? x=1/4y^2

Answer 1

The value of p is 1

Explanation:

we know that

The standard form of the equation of a horizontal parabola is

`(y - k)^(2)= 4p(x - h)`

where

(h,k) is the vertex

p≠ 0

If p > 0, the parabola opens to the right, and if p < 0, the parabola opens to the left.

In this problem we have

`x=(1)/(4)y^(2)`

Convert to standard form

`y^(2)=4x`

The vertex is the point (0,0)

`4p=4`

`p=1` -----> p > 0, the parabola opens to the right