Answer:
A. 2π s
Step-by-step explanation:
Assuming the pendulum is on the Earth and g = 10m/s2, the period is 2π s, if the length is 10 m.
T = 2π √(L/g)
Period of a pendulum is:
Given L = 10 m and g = 10 m/s²:
T = 2π √(10 m / (10 m/s²))
T = 2π s
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