Question

Which graph shows the solution to the system of linear inequalities?

y > 2/3x + 3

y ≤ 1/3x + 2




option B is the answer (pictured)

Answer 1

its B simple

Explanation:

right on edg 2020

Answer 2

Observe the attached image.

Explanation:

We have the following linear inequalities

`y > (2)/(3)x + 3\\\\y \leq (1)/(3)x + 2`

Graph the lines corresponding to each inequality

`y > (2)/(3)x + 3` →
`y = (2)/(3)x + 3`

Cut with the y axis:

y = 3

Cut with the x axis:

`0 = (2)/(3)x + 3`

`-3 = (2)/(3)x`

`x = -4.5`

`y \leq (1)/(3)x + 2` →
`y = (1)/(3)x +2`

Cut with the y axis:

y = 2

Cut with the x axis:

`0 = (1)/(3)x + 2`

`-2 = (1)/(3)x`

`x = -6`

Now graph the two lines

For
`y > (2)/(3)x + 3`

The region is made up of all the points that are above the line
`y =(2)/(3)x + 3`

For
`y \leq (1)/(3)x + 2`

The region is made up of all the points that are on the line and below
`y = (1)/(3)x +2`

The final region will be the interception of both regions

Observe the attached image.

The system shown in the image you attached is:

`y > (2)/(3)x + 3\\\\y \leq -(1)/(3)x + 2`