Answer:
The two planes are 230 miles away after one hour.
Explanation:
We know the speed of airplanes A and B and we know the angle between the speeds of both.
If the speed of plane A is 200 miles per hour, and the speed of plane B is 300 miles per hour, then after 1 hour the plane A will have traveled 200 miles and the plane B will have traveled 300 miles.
If we call c the distance between the two planes then we can use a triangle of sides, a, b and c
Where
![a = 200\ miles\\\\b = 300\ miles](https://img.qammunity.org/2020/formulas/mathematics/middle-school/up4btgve7iqbqtg64gin1ernbqsih07gtn.png)
c = distance between both planes
Side c is opposite the angle of 50 °.
Then we use the law of cosine to find c.
![c ^ 2 = a ^ 2 + b ^ 2 - 2abcos(50\°)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bjnaetp34smm6017ea4w4o54b0zwbzbkeo.png)
![c ^ 2 = 200 ^ 2 + 300 ^ 2 - 2*200*300cos(50\°)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/zxsfqxuovik9etoclxt659l106l8wesbxb.png)
![c = √(200 ^ 2 + 300 ^ 2 - 2*200*300cos(50\°))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kak1hp2uf7s70gy893apac2vawibasredx.png)
![c = √(52865.49)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/h10sfk545bb2tdrwnuuypgbskry126w7oc.png)
![c = 230\ miles](https://img.qammunity.org/2020/formulas/mathematics/middle-school/cx32hwsje349vf6qloet3hxgakhjxbc0ob.png)