Answer:
b) 414nm
Step-by-step explanation:
let λ1 be the wavelenght of light in a vacuum and λ2 be the wavelength of light in water.
the relationship between the refractive index wavelenghts in a vacuum and in water is given by:
n = λ1/λ2
λ2 = λ1/n
= (550)/(1.33)
= 413.53 nm
≈ 414nm
Therefore the wavelength of light in water is 414mn.