Question

A force is applied with a magnitude of 70 N at an angle of 50 degrees from the horizontal. What are the horizontal and vertical components of force?

Answer 1

Fy = 53.62 N

Fx ≈ 50 N

Step-by-step explanation:

let Fx be the horizontal component of the applied force and Fy be the vertical component of the applied force then:

Fy = F×sin(∅)

= (70)×sin(50°)

= 53.62 N

Fx = F×cos(∅)

= (70)×cos(50°)

≈ 50 N