Sure.
The common difference is 1/3
d = 8/15 - 1/5 = 8/15 - 3/15 = 5/15 = 1/3
d = 13/15 - 8/15 = 5/15 = 1/3
So the seventh term is
S_n = S_1 + (n-1)d
S_7 = (1/5) + 6(1/3) = 11/5
The sum is the average of the first and last times the number of elements
(1/2)(1/5 + 11/5)(7) = 7(6/5) = 42/5 = 8.4
Answer: 42/5