Question

A steam turbine has an inlet of 3 kg/s water at 1200 kPa, 350 °C and velocity 15 m/s. The exit is at 100 kPa, 150 °C and very low velocity. Find the specific work and power produced?

Answer 1

W = 377.312 KJ/kg

P =1131.937 KW

Step-by-step explanation:

`\dot m = 3 kg/s`

V_1 =15m/s

P_1 = 1200kPa

T_1 = 350 DEGREE C

For above value , and from super heated tables H_1 = 3153.3 Kj/kg

P_2 = 100kPa

T_2 = 150 degree C

For above value , and from super heated tables H_2 = 2776.1 Kj/kg

v_2 = 0

from energy equation

`Q + H_1 +(v_1^2)/(2) = W + H_2 +(v_2^2)/(2)`

`H_1 +(v_1^2)/(2) = W + H_2` { V_2 = 0, Q =0}

`3153.3 + (15^2)/(2) = 2776.1 +W`

W = 377.312 KJ/kg

power is given as

`P = \dot m * w`

P = 3*377.312 = 1131.937 KW