Question

What is the maximum volume flow rate, in m^3/hr, of water at 15.6°C a 10-cm diameter pipe can carry such that the flow will be laminar?

Answer 1

Q = 0.00017597 m3/sec

Step-by-step explanation:

given data:

temperature of water 15.6 degree celcius

diameter = 10cm =0.1 m

dynamix viscosity of water = .0011193 kg/m sec at 15.6 degree celcius

density of water at 15.6 degree = 999.07 kg/m3

for laminar flow REYNOLD NUMBER < 2000

maximum flow rate =area*velocity

Reynold number
`Re = (\rho vd)/(\mu)`

`v = (Re \mu)/(\rho d)`
`v = (2000*0.00011193)/(999.07 *0.1)`

v = 0.022406 m/sec

`Q =(\pi)/(4) d^2 v`

where Q is flow expressed in m^3/s

`Q =(\pi)/(4) *0.1^2 *0.022406`

Q =0.00017597 m3/sec