Answer:
D.Its lateral surface area is equal to the product of its perpendicular height and the circumference of its base.
Explanation:
Right circular cylinder :It consist of cylinder and two circular bases .
Let a right circular cylinder of radius r and height h.
Lateral surface area of right circular cylinder =
![2\pi rh](https://img.qammunity.org/2020/formulas/mathematics/middle-school/62ik5vlmubqhshfdb5o80ip4eswj31sewf.png)
Where r=Radius of cylinder
h=Height of cylinder
Total surface area of cylinder=
![2\pi rh+2\pi r^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/1yk8zao4jarx6ve2w681q6mp0aybyfx8k8.png)
Volume of right circular cylinder =
![\pi r^2h](https://img.qammunity.org/2020/formulas/mathematics/high-school/iv5zuf12kycckuw06sx5hm0mhmaznx0qq7.png)
Circumference of circular base =
![2\pi r](https://img.qammunity.org/2020/formulas/mathematics/high-school/ir4p1njkse3vr4g086to99olcbhyx0uhrq.png)
Hence, the lateral surface area of right circular cylinder =
![2\pi r*h](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lm1x2nyxcdf0bgr69qt68985xv7nxqjg3z.png)
Therefore, option D is true.
D.Its lateral surface area is equal to the product of its perpendicular height and the circumference of its base.