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The four points (−2, 5), (−2, −1), (5, −1), and (3, 5) are the vertices of a polygon. What is the area, in square units, of this polygon?

27 units2
33 units2
36 units2
51 units2

2 Answers

4 votes

Answer:

the area, in square units, of this polygon is 36 units2

User Macy Abbey
by
8.8k points
3 votes

Answer:

The area of the given Polygon is:


36\ unit^2

Explanation:

The polygon is in the shape of the trapezoid with two bases AB and CD and altitude as: AD

Now we know that the area of trapezoid is given by:


\text{Area}=(1)/(2)* (\text{Sum of bases})* \text{Altitude}

i.e.

Here


\text{Area}=(1)/(2)* (AB+CD)* AD

Now, we find the length of AB,CD and AD using distance formula.

A is located at (-2,5)

B at (3,5)

C at (5,-1)

D at (-2,-1)


AB=√((-2-3)^2+(5-5)^2)\\\\i.e.\\\\AB=√((-5)^2+0^2)\\\\i.e.\\\\AB=√(25)\\\\i.e.\\\\AB=5\ units


CD=√((5-(-2))^2+((-1)-(-1))^2)\\\\i.e.\\\\CD=√(7^2+0^2)\\\\i.e.\\\\CD=7\ units


AD=√((-2-(-2))^2+(5-(-1))^2)\\\\i.e.\\\\AD=√(0^2+6^2)\\\\i.e.\\\\AD=6\ units

Hence, the area of Trapezoid is:


Area=(1)/(2)* (5+7)* 6\\\\i.e.\\\\Area=36\ unit^2

The four points (−2, 5), (−2, −1), (5, −1), and (3, 5) are the vertices of a polygon-example-1
User Demz
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8.0k points