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On an inclined plane with angle α to the horizontal it leans a rod which, due to a guide, it can move only vertically.Find the velocity "u" with which will climb the rod when the inclined plane is moved to the left with the constant velocity "v".

v,alpha
---------------
u=?

Please help me with explanations and a draw i don't get it when in decomposition of "u" what vector it will have the value = value of v and i don't know how to recognize the alpha angle in the decomposition.

On an inclined plane with angle α to the horizontal it leans a rod which, due to a-example-1
User Sam Woods
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1 Answer

4 votes

Answer:

u = - tan * v

Step-by-step explanation:

Here is a different perspective. An observer that moves along the incline has a velocity w. The velocity v of the incline is equal to the horizontal componant of the observer with the opposit sign. The velocity u of the rod is the vertical component of the observer.

You get the following equations:

u = w sin

v = - w cos

Dividing both equations give:

u/v = -tan

u = - tan * v

On an inclined plane with angle α to the horizontal it leans a rod which, due to a-example-1
User Chris Hilton
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8.0k points