Question

If it takes 5 hours to produce 8.0 kg of alcohol, how any days will it take to consume 1000 kg of glucose?

Answer 1

It takes 21.3 days

Further explanation

Given

5 hr = 8 kg Alcohol

Required

Days to consume 1000 kg of glucose

Solution

Alcoholic fermentation⇒ glucose produces ethanol and carbon dioxide,

C₆H₁₂O₆ → 2 C₂H₅OH + 2CO₂

mol ethanol :

`\tt (5000~g)/(46~g/mol)=108.7~moles`

moles of glucose to produce 108.7 moles ethanol :

`\tt (1)/(2)* 108.7=54.35`

54.35 moles = 5 hours

moles of 1000 kg of glucose :

`\tt (10^6~g)/(180~g/mol)=5555.5~moles`

So for 5555.5 moles, it takes :

`\tt (5555.5)/(54.35)* 5~hours=511.085~h=21.3~days`