Question

What are the molar concentrations of the ions in 0.26 M aluminum sulfate?

C(A13+) =
C(SO4^2-) =

Answer 1

c(Al³⁺) = 0.52 mol·L⁻¹; c(SO₄²⁻) = 0.84 mol·L⁻¹

Step-by-step explanation:

One mole of aluminium sulfate produces 2 mol of aluminium ions and 3 mol of sulfate ions.

If we apply the same proportionality, 0.26 mol of Al₂(SO₄)₃ produces 0.52 mol of Al³⁺ions and 0.84 mol of SO₄²⁻ ions.

Al₂(SO₄)₃(aq) ⟶ 2Al³⁺(aq) + 3SO₄²⁻(aq)

I/mol·L⁻¹: 0.26 0 0

C/mol·L⁻¹: -0.26 +0.52 +0.84

E/mol·L⁻¹: 0 0.52 0.84