Answer:
$83,320
Explanation:
The formula to apply here is;
![A=P(1+(r)/(n) )^(nt)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/50x0ieoo6jfvqpr5cf29hjveiuux7xz5uu.png)
where;
A=Amount at the end
P=the amount to invest/principal
r=rate of interest as a decimal
n=number of compoundings in a year
t=time in years
Given that;
A=$400,000
P=?
r=8%=0.08
n=2
t=20
Substitute values in equation
![A=P(1+(r)/(n) )^(nt) \\\\\\400,000=P(1+(0.08)/(2) )^(2*20) \\\\\\400,000=P(1+0.04)^(40) \\\\\\\\400,000=P(1.04)^(40) \\\\\\400,000=P(4.80102062794)\\\\\\\\(400,000)/(4.80102062794) =(4.80102062794P)/(4.80102062794) \\\\\\83315.617=P\\\\](https://img.qammunity.org/2020/formulas/mathematics/middle-school/am6knk2iyaamotw4nfjs0b2i5ij5e3cqnb.png)
P=$83,320 (to the nearest dollar)