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What is the solution to 2x^2+x+2=

User Willascend
by
8.1k points

2 Answers

3 votes

Answer:

2x2 + x + 2

Explanation:

User Lanexbg
by
7.8k points
5 votes

For this case we have the following equation:


2x ^ 2 + x + 2 = 0

The roots will be given by:


x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}

Where:


a = 2\\b = 1\\c = 2

Substituting the values:


x = \frac {-1 \pm \sqrt {1 ^ 2-4 (2) (2)}} {2 (2)}\\x = \frac {-1 \pm \sqrt {1-16}} {4}\\x = \frac {-1 \pm \sqrt {-15}} {4}\\x = \frac {-1 \pm i \sqrt {15}} {4}

We have two roots:


x_ {1} = \frac {-1 + i \sqrt {15}} {4}\\x_ {2} = \frac {-1-i \sqrt {15}} {4}

ANswer:


x_ {1} = \frac {-1 + i \sqrt {15}} {4}\\x_ {2} = \frac {-1-i \sqrt {15}} {4}

User Yamilet
by
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