Question

A particle has a charge of 5.2 × 10-19 coulombs and experiences a force of 9.5 × 10-15 newtons when it travels through a magnetic field with strength 2.2 × 10-1 tesla. What is the speed of the particle?

1.9 × 104 meters/second



2.2 × 104 meters/second



4.9 × 104 meters/second



8.3 × 104 meters/second

5 MINUTE TIME LEFT NEED ANSWER WITHIN 5 MINUTES PLEASE VERY IMPORTANT

Answer 1

Step-by-step explanation:

F=Bqv (in magnetic field)

9.5*10^-15=(5.2*10^-19)(2.2*10^-1)*v

solve for v.

Answer 2

Answer : The speed of particle is
`8.3* 10^4m/s`

Explanation :

Magnetic force : It is defined as when a charged particle moves in magnetic field, then force is exerted on the moving charged particle. In this the force is perpendicular to both the velocity of the charge and the magnetic field.

Formula used :

`F=qvB`

where,

F = magnetic force =
`9.5* 10^(-15)N`

q = charge =
`5.2* 10^(-19)C`

v = velocity of charge = ?

B = magnetic field strength =
`2.2* 10^(-1)tesla`

Now put all the given values in the above formula, we get:

`F=qvB`

`9.5* 10^(-15)N=(5.2* 10^(-19)C)* v* (2.2* 10^(-1)tesla)`

`v=8.3* 10^4m/s`

Therefore, the speed of particle is
`8.3* 10^4m/s`