Question

If Jill starts out at 20 m/s, and in 10 s speeds up to 40 m/s, what is her acceleration?

O 3 m/s2
O 200 m/s2
02 m/s2
01 m/s2

Answer 1

The acceleration of Jill is
`\bold{2 \ m / s^(2)}` if he starts out at the velocity 20 m/s and in 10 s speeds up to 40 m/s.

Step-by-step explanation:

From given, we came to know that the Jill starts out at 20 m/s, and in 10 s speeds up to 40 m/s, to find acceleration of Jill, we know that acceleration is ratio of velocity to time change.

The acceleration is given by the formula:

`\text { Acceleration }=\frac{\text { Change in velocity }}{\text { Change in time }}`

We know that change in velocity as 20 m/s to 40.0 m/s and change time as 10 s.

`\Rightarrow \text { Acceleration }=(40-20)/(10)`

`\therefore \text { Acceleration }=2 \ \mathrm{m} / \mathrm{s}^(2)`

Thus, acceleration of Jill will be
`\bold{2 \ m / s^(2)}`

Answer 2

`2 m/s^2`

Step-by-step explanation:

The acceleration of an object (or a person, as in this case) is given by

`a=(v-u)/(t)`

where

v is the final velocity

u is the initial velocity

t is the time interval

In this problem,

u = 20 m/s

v = 40 m/s

t = 10 s

Therefore Jill's acceleration is

`a=(40-20)/(10)=2 m/s^2`