Answer:
a) 280MPa
b) -100MPa
c) -0.35
d) 380 MPa
Step-by-step explanation:
GIVEN DATA:
mean stress
![\sigma_m = 90MPa](https://img.qammunity.org/2020/formulas/engineering/college/9zin4tfaczre61vc1spai4ol5mwn68l4gf.png)
stress amplitude
![\sigma_a = 190MPa](https://img.qammunity.org/2020/formulas/engineering/college/1n8qmr2pe2qcm0lbytbgerz24ctxhft2sr.png)
a)
![\sigma_m =(\sigma_max+\sigma_min)/(2)](https://img.qammunity.org/2020/formulas/engineering/college/56cnvyhp8h7by3bduqemfy8wrciw4e6umm.png)
--------------1
![\sigma_a =(\sigma_(max)-\sigma_(min))/(2)](https://img.qammunity.org/2020/formulas/engineering/college/bvlpj8k85s71apy59am3s52yh09821x7ux.png)
-----------2
solving 1 and 2 equation we get
![\sigma_(max) = 280MPa](https://img.qammunity.org/2020/formulas/engineering/college/7lynp3ofyl1odbvtb9npwdcslrs55wxll0.png)
b)
![\sigma_(min) = - 100MPa](https://img.qammunity.org/2020/formulas/engineering/college/wwxakavlgzcjdiyj74jde8oitpwnz6j0ii.png)
c)
stress ratio
![=(\sigma_(min))/(\sigma_(max))](https://img.qammunity.org/2020/formulas/engineering/college/79i476l4s2yzsl3xweovrxqmzr9j9hlq5s.png)
![=(-100)/(280) = -0.35](https://img.qammunity.org/2020/formulas/engineering/college/75ux4ihn3hg7ratmbaycly64bz55ozbwop.png)
d)magnitude of stress range
![=(\sigma_(max) -\sigma_(min))](https://img.qammunity.org/2020/formulas/engineering/college/lfueqq3ptgci80sy6xjjq4u7zryyejf1wy.png)
= 280 -(-100) = 380 MPa